Moment of a Force About a Point (Scalar Calculations)

The moment of a force is the tendency of some forces to cause rotation. An easy way to visualize the concept is to imagine a box set on a smooth surface. If you were to apply a force to the center of the box, it would simply slide across the surface without rotating. If you were instead to push on one side of the box it will start rotating as it moves. Even though the forces have the same magnitude and the same direction, they cause different reactions. This is because the off center force has a different point of application, and exerts a moment about the center of the box, whereas the force on the center of the box does not exert a moment about the boxes center point.

Pushing a box with an on center force and pushing a box with an off center force
If we push a box in the center it will simply begin sliding. If we push a box off-center, we will exert a moment and the box will rotate in addition to sliding.

Just like forces, moments have a magnitude (the degree of rotation it would cause) and a direction (the axis the body would rotate about). Determining the magnitude and direction of these moments about a given point is an important step in the analysis of rigid body systems (bodies that are both rigid and where forces are not concurrent). The scalar method below is the easiest way to do this in simple two dimensional problems, while alternative vector methods work best in more complex three dimensional systems.

The Scalar Method in 2 Dimensions

In discussing how to calculate the moment of a force about a point via scalar quantities, we will begin with the example of a force on a simple lever as shown below. In this simple lever there is a force on the end of the lever, distance d away from the center of rotation for the lever (point A) where the force has a magnitude F.

Moment About A Point
The magnitude of the moment that force F exerts about point A on this lever will be equal to the magnitude of the force times distance d.

When using scalar quantities, the magnitude of the moment will be equal to the perpendicular distance between the line of action of the force and the point we are taking the moment about.

\[M=F*d\]

To determine the sign of the moment, we determine what type of rotation the force would cause. In this case we can see that the force would cause the lever to rotate counterclockwise about point A. Counterclockwise rotations are caused by positive moments while clockwise rotations are caused by negative moments.

Another important factor to remember is that the value d is the perpendicular distance from the force to the point we are taking the moment about. We could measure the distance from point A to the head of the force vector, or the tail of the force vector, or really any point along the line of action of force F. The distance we need to use for the scalar moment calculation however is the shortest distance between the point and the line of action of the force. This will always be a line perpendicular to the line of action of the force, going to the point we are taking the moment about.

Moment About a Point
Distance d always needs to be the shortest length between the line of action of the force and the point we are taking the moment about. This distance will be perpendicular to the line of action of the force.

The Scalar Method in 3 Dimensions

For three dimensional scalar calculations, we will still find the magnitude of the moment in the same way, multiplying the magnitude of the force by the perpendicular distance between the point and the line of action of the force. This perpendicular distance again is the minimum distance between the point and the line of action of the force. In some cases, finding this distance may be very difficult.

Moments in 3 dimensions
For moments in three dimensions, the moment vector will always be perpendicular to both the force vector F and the distance vector d.
The Right Hand Rule
To use the right hand rule, align your right hand as shown so that your thumb lines up with the axis of rotation for the moment and your curled fingers point in the direction of rotation for your moment. If you do this, your thumb will be pointing in the direction of the moment vector. Adapted from Public Domain image by Schorschi2.

Another difficult factor in three dimensional scalar problems is finding the axis of rotation, as this is now more complex than just 'clockwise or counterclockwise'. The axis of rotation will be a line traveling through the point we are taking the moment about that is perpendicular to both the force vector and the perpendicular displacement vector (the vector going from the point we are taking the moment about to the point of application of the force. While this is possible in any situation, it becomes very difficult if the force or displacement vectors do not lie in one of the three coordinate directions.

To further find the direction of the moment vector (which will act along the established line for axis of rotation) we will use the right hand rule in a modified form. Wrap the fingers of your right hand around the axis of rotation line with your fingertips curling in the direction the body would rotate. If you do this, your thumb should point out along the line in the direction of the moment vector. This is an important last step, because we can rotate clockwise of counter-clockwise in about any given axis of rotation. With the final moment vector, we known not only the axis of rotation, but which way the body would rotate about that axis.

Worked Problems:

Question 1:

What is the moment that Force A exerts about point A? What is the moment that Force B exerts about Point A?

Problem 1 Diagram

Solution:



Question 2:

What is the moment that this force exerts about point A? What is the moment this force exerts about point B?

Problem 2 Diagram

Solution:



Question 3:

What are the moments that each of the three tension forces exert about point A (the point where the beams come together)?

Problem 3 Diagram

Solution: